Y=2x^2-12x+1

Solution for Y=2x^2-12x+1 equation:

=2Y^2-12Y+1

We move all terms to the left:

-(2Y^2-12Y+1)=0

We get rid of parentheses

-2Y^2+12Y-1=0

a = -2; b = 12; c = -1;
Δ = b2-4ac
Δ = 122-4·(-2)·(-1)
Δ = 136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{136}=\sqrt{4*34}=\sqrt{4}*\sqrt{34}=2\sqrt{34}$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-2\sqrt{34}}{2*-2}=\frac{-12-2\sqrt{34}}{-4}
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+2\sqrt{34}}{2*-2}=\frac{-12+2\sqrt{34}}{-4}
$